Question

alright i got this much so far can someone help with the rest please
2x^2-6x-36
First look for the GCF
GCF=2
Next divide the problem by the GCF
2(x^2-3x-18)

Answer 1

Divide. What's the problem?

Answer 2

i dont know the how to do the rest of this i'm trying to explain how to factor but i'm stuck here I know the answer is 2(x+3)(x-6) but i don't know how to get to that point

Answer 3

Okay! So you want to factorise it.

Answer 4

yes i'm trying to factor this out

Answer 5

It's easy. Listen. Divide the middle term ( -3x ) in two part so that when you multiply the two then you get the product equal to first ( x^2 )and last ( -18 ) terms. And if you add the two parts then you get -3x back.

Answer 6

Here we have x^2-3x-18
So, We have to divide -3x in 2 parts such that their product is -18x^2.
Let us divide them -3x in -6x and +3x. If we multiply -6x and +3x then we get -18x^2 and if we add them we get -3x back.

Answer 7

2(x^2-3x-18)gives me 2(x+3) (x-6) right?

Answer 8

Yes, right

Answer 9

Now expression becomes x^2-6x+3x-18 which is equal to x(x-6)+3(x-6) which further becomes (x+3)(x-6)

Answer 10

Problem Solved. Mission Accomplished. :)

Answer 11

2x^2-6x-36
First look for the GCF
GCF=2
Next divide the problem by the GCF
2(x^2-3x-18)
2(x+3)(x-6)
X^2 -6x + 3x -18
x(x-6)+3(x-6)
(x+3)(x-6)
so it would look like this?

Answer 12

No. multiply it with 2 also. I just solved the expression.

Answer 13

where do tou multiply two

Answer 14

The final would be : 2(x^2-3x-18)
2[x^2 -6x + 3x -18]
2[x(x-6)+3(x-6)]
2(x+3)(x-6)

Answer 15

oh i got it now thanks dude

Answer 16

You're welcome. I'm happy to help.

Answer 17

I'll log out now. I have to go to get a haircut. Tomorrow is my NCC training. Take Care. See You Again. :)

Answer 18

ok c ya later