Question

prove siny +tany/over/ 1+secy=siny

Answer 1

\[\frac{ siny+tany }{ 1+secy }=siny\]?

Answer 2

yes

Answer 3

\[\frac{ siny+\frac{ siny }{ cosy } }{ 1+\frac{ 1 }{ cosy } }\]


Make those into common denominators and simplify it out. It'll gert your answer : )

Answer 4

oh but i seem to be stuck on this part sinycosy=siny/cosy large fraction 1=cosy/cosy

Answer 5

Alrighty, lemme see : )

Answer 6

I made a mistake the equal signs should be + sign

Answer 7

\[\frac{ siny + \frac{ siny }{ cosy } }{ 1+\frac{ 1 }{ cosy } }\]Common denominator makes this:
\[\frac{ \frac{ sinycosy+siny }{ cosy } }{ \frac{ cosy+1 }{ cosy } }\]I can factor out the sin on top to have:
\[\frac{ \frac{ \sin(cosy+1) }{ cosy } }{ \frac{ cosy+1 }{ cosy } }\] Can ya see where this will lead now? :P

Answer 8

let me see

Answer 9

I cant really tell how you are seeting them up

Answer 10

do you think you could draw the equation

Answer 11

Yeah, sure.

Answer 12

thank you

Answer 13

Now combining into one fraction I get: