please help me ...
divide:(y^2-y-12)/(y^2-6y+8 by (y^2+2y-15)/(y^2-7y+10)

Question

please help me ...
divide:(y^2-y-12)/(y^2-6y+8 by (y^2+2y-15)/(y^2-7y+10)

anonymous · Answer

$$\frac{y^2-y-12}{y^2-6y+8}\times \frac{y^2-7y+10}{y^2-2y-15}$$ is a start
then factor
then cancel

anonymous · Answer

ok thanks so much

anonymous · Answer

yw
good luck with the factoring

anonymous · Answer

i am good at canceling but i need help with factoring can u plz help me with the factoring

anonymous · Answer

@dumbcow can u please help me factor this

anonymous · Answer

@Compassionate

dumbcow · Answer

"i am good at cancelling"

haha sorry but thats funny

anonymous · Answer

it is ok i am stupid when it comes to math

compassionate · Answer

Factoring just means breaking it down into smaller parts 

For example, lets take the first one. $$x^2 - y - 12$$

(x   )(x    ) 

Because x * x = x^2 
Then we wil lsay, "what two products multiplied together equal 12, and added equal -y?
 

Well, you'll find it's not factorable because no two terms can be multiplied but their product be -y.

dumbcow · Answer

so for factoring you want to find factors of constant which add up to middle coefficient
$$y^{2} + by + c = (y+e)(y+f)$$
e*f = c
e+f = b

anonymous · Answer

oh ok i see