Question

3cosx+3=2sin^2x

Answer 1

using the pythagorean identity
\[\sin^{2} x = 1- \cos^{2}x\]
which results in the quadratic form
\[2u^{2} +3u +1 = 0\]
where u = cos x

Answer 2

@vc123 , from there factor and solve for u which will allow to solve for x

let me know if you follow?

Answer 3

oh my gosh! thank you so much! it's been a while since i've reviewed my trig identities, i guess i should do that. thank you!

Answer 4

haha yeah i would always keep a trig reference sheet to look up identities

your welcome