Question

solve using substitution
1) 6x + 2y = 0
4x + y = -1

2) 3x + 2y = -4
x + 2y = -8

3) 5x - 4y = 14
x - 2y = -2

4) x + 3y = -4
4x + 5y = 5

5) x + 3y = -5
2x - y = 18
just answers please im running outa time!

Answer 1

hi

Answer 2

http://openstudy.com/users/kiannaandrews#/updates/52128aeee4b00ebc7dbf9581

Answer 3

i know i posted again so itall go back to the top! :P

Answer 4

and umm...working out going to the gym and eating right y?

Answer 5

i would just like help wwith my math please!

Answer 6

lol

Answer 7

yeah i thought this was a school/ homework help site not a creep on people site!

Answer 8

let's do the 1st one, no that abb0t didn't already go through it

6x + 2y = 0
4x + y = -1

can you solve for "y" in the 2nd one?

Answer 9

y is -1 right?
abbOt did go over it but i just need answers now im running outa time and im quite frustrated with this!

Answer 10

@love_jessika15

Answer 11

well, \(\bf y \ne -1\)

Answer 12

so 4x-1=-1?

Answer 13

well, you're supposed to isolate "y" on say, the left-hand side

Answer 14

so -1y=4x-1?

Answer 15

4x + y = -1
# subtract 4x from both sides

y = -1 -4x

\(\bf 6x + 2y = 0\\
4x + y = -1\\
\color{red}{y = -1 -4x}\\
\textit{let's use THAT "y" in the 1st equation}\\
6x + 2y = 0 \implies 6x + 2(\color{red}{-1 -4x}) = 0\)

Answer 16

so, from there, just solve for "x"