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Mathematics 8 Online
OpenStudy (anonymous):

Finding asymptotes? http://oi43.tinypic.com/210yr7l.jpg

OpenStudy (goten77):

asymptotes are what make the top or bottom equal 0 so for the bottom since those are all being multiplied if just 1 of them is made to equal 0 then it will make the whole denominator multiple out to 0

OpenStudy (anonymous):

So they would be x=-3,-1. 2 and y=0?

OpenStudy (anonymous):

*-3,-1,2

OpenStudy (goten77):

also the top can equal 0 for anotehr asymptopte i cant spell it XD

OpenStudy (anonymous):

Okay thank you! And awesome username btw.

OpenStudy (goten77):

i think im forgetting something....

OpenStudy (anonymous):

excuse me but I want to add another information , the asymptotes exist when the denominator is 0 and the denominator must not cancel the value that makes it 0 with the numerator e.g \[\frac{ x-2 }{ (x-2)(x+1) }\] x=2 is not a vertical asymptote, unlike x=-1 besides the zeroes of neumerator has nothing to do with vertical asymptotes

OpenStudy (goten77):

ah ye... its the powers that determine the horizontal asymptotes... which is what i needed to get at next.... XD and some more stuff

OpenStudy (anonymous):

yes that's right @Goten77 but that's completely another thing , however , niether horizontal nor oblique asymptotes exist in f(x)

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