Find the equation of a parabola passing through (-4, -6) whose vertex is at (-2,-4) and whose axis is parallel to the x-axis. the answer is (y+4)^2 = -2(x+2).. how to get the P given the points, vertex? Help me please. Show it to me step by step. Thank you.

Question

anonymous · Answer

vertex is $(-2,4)$ and  the axis of symmetry is parallel to the $x$ axis, so you know it looks like 
$$(y+4)^2=a(x+2)$$ is that much clear ?

anonymous · Answer

oops i meant vertex is $(-2,-4)$

anonymous · Answer

yes. and how about a? how to get a?

anonymous · Answer

for that you need to use the second point

anonymous · Answer

replace $x$ by$-4$ and $y$ by $-6$ and solve for $a$

anonymous · Answer

$$(y+4)^2=a(x+2)$$
$$(-6+4)^2=a(-4+2)$$

anonymous · Answer

hooray! got it now!!

anonymous · Answer

super thank you :)))

anonymous · Answer

you get 
$$4=-2a$$ and so $a=-2$

yw!!