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Mathematics 10 Online
OpenStudy (anonymous):

Factor the polynomial: 32a^2b^2+16ab^2+2b^2

OpenStudy (anonymous):

\(32a^2b^2+16ab^2+2b^2\) Start by factoring out a common term.

OpenStudy (anonymous):

The common term would be 2 , correct?

OpenStudy (anonymous):

That would be one factor. There is one more.

OpenStudy (anonymous):

Like 4 too!

OpenStudy (anonymous):

No, 4 is not common to all terms. 2 is the only constant that can be factored from all terms.

OpenStudy (anonymous):

Okay, so after that what would be my next step?

OpenStudy (anonymous):

2 is only part of the common factor. Have you found the rest of it?

OpenStudy (anonymous):

Divide each term by 2 and look at what is left.

OpenStudy (anonymous):

A and b^2

OpenStudy (anonymous):

Ok, so divide all terms by \(b^2\) and tell me what is left.

OpenStudy (anonymous):

Give me a sec

OpenStudy (anonymous):

Take your time.

OpenStudy (anonymous):

Wait you can only divide b^2 and not a!

OpenStudy (anonymous):

One step at a time. First divide all terms by 2. Then divide all terms by \(b^2\). See what you have left. And yes, it is true that you cannot divide all terms by a, but it can be factored further.

OpenStudy (anonymous):

What do you mean by factored forward?

OpenStudy (anonymous):

Show me what you have done. You factored out the \(2b^2\) - show me what you have left.

OpenStudy (anonymous):

2b^2(16a+8a+1)

OpenStudy (anonymous):

Almost. \(2b^2(16a^2+8a+1)\) Keep track of the exponents.

OpenStudy (anonymous):

Factor the remaining expression just like any other quadratic expression.

OpenStudy (anonymous):

So far I have 2b^2(4a+____)(4a+____)

OpenStudy (anonymous):

Yes. That is exactly it.

OpenStudy (anonymous):

The last numbers in each factor must multiply to be +1. What are the factors of 1?

OpenStudy (anonymous):

1 (:

OpenStudy (anonymous):

Thank you so much for the help(: I appreciate it so much (:

OpenStudy (anonymous):

Your welcome.

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