Factor the polynomial: 32a^2b^2+16ab^2+2b^2
\(32a^2b^2+16ab^2+2b^2\) Start by factoring out a common term.
The common term would be 2 , correct?
That would be one factor. There is one more.
Like 4 too!
No, 4 is not common to all terms. 2 is the only constant that can be factored from all terms.
Okay, so after that what would be my next step?
2 is only part of the common factor. Have you found the rest of it?
Divide each term by 2 and look at what is left.
A and b^2
Ok, so divide all terms by \(b^2\) and tell me what is left.
Give me a sec
Take your time.
Wait you can only divide b^2 and not a!
One step at a time. First divide all terms by 2. Then divide all terms by \(b^2\). See what you have left. And yes, it is true that you cannot divide all terms by a, but it can be factored further.
What do you mean by factored forward?
Show me what you have done. You factored out the \(2b^2\) - show me what you have left.
2b^2(16a+8a+1)
Almost. \(2b^2(16a^2+8a+1)\) Keep track of the exponents.
Factor the remaining expression just like any other quadratic expression.
So far I have 2b^2(4a+____)(4a+____)
Yes. That is exactly it.
The last numbers in each factor must multiply to be +1. What are the factors of 1?
1 (:
Thank you so much for the help(: I appreciate it so much (:
Your welcome.
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