Question

Another difficult problem, I need help on.
x+3y-z=-1
2y+z=0
2z=12

Answer choice:
A. x = 10, y = 3, z = 6
B. x = 1, y = 3, z = 6
C. x = 14, y = -3, z = 6

Answer 1

k lets start at the bottom
if \(2z=12\) then what is \(z\) ?

Answer 2

Solve for z first. 2z = 12 --> z = 6

Answer 3

6 (:

Answer 4

@satellite73

Answer 5

Plug z into second equation. 2y + 6 = 0. --> 2y = -6 --> y = -3

Answer 6

C. X=14, Y=-3 , Z=6...

Answer 7

Uh huh, then? :o

Answer 8

Thank's @chirag.ahir :)

Answer 9

lol but I kinda need to know how to solve this..

Answer 10

Plug both into x + 3y - z = -1.
x + 3(-3) - 6 = -1
x - 9 -6 = -1
x - 15 = -1
x = 14.

Answer 11

Thus, your answer will be x = 14, y = -3, and z = 6.

Answer 12

I hope this helped!

Answer 13

Thank you!! :)

Answer 14

No problem! I am certainly glad to help.