with the x-intercept as 5x-6y=-15 parallel to 2x-8y=9

Question

anonymous · Answer

Is part of the question missing? What comes before the "with"?

anonymous · Answer

its solving equations of a line and putting it in standard form

anonymous · Answer

In the mean time, 
2x - 8y = 9
     - 8y = 9 - 2x
          y = -9/8 + x/4

anonymous · Answer

OK, so we already have one standard form from above. x/4 = (1/4)x so the slope of that particular line is 1/4. The parallel line will have the same slope.

To find x-intercept, we plug 0 in for y right?

anonymous · Answer

howd you get x/4?

anonymous · Answer

(-2x)/(-8) right?

anonymous · Answer

5x - 6(0) = -15 ==> x =?

When you have this value then you can say: because this is the x-intercept of the line, the line goes through the point (?, 0)

Now you have the classic problem of finding the line given slope and 1 point. You can do that right?

anonymous · Answer

First. we determine the x-intercept of 5x - 6y = -15   (a,0)
                   when y = 0, x = -3, so x intercept is (-3, 0)
                   we use the form y = mx + b
                   since the line is parallel to 2x - 8y = 9, it will have the same slope
                   rewriting the equation in slope intercept form
                                                          y = (2/8)x - (9/8)
                  slope is 2/8
                  equation now is  y = (2/8)x + b
                  we now need to find b, which is the y-intercept
                    using that point (-3,0), we can plug that in y = (2/8)x + b
                   and can now solve for b
                   0 = (2/8)(-3) + b
                   
                    I guess you can do the rest.