Question

2^x + 2^-x=5

Answer 1

Use your properties of natural log to solve for "x". Remember that \(a^{x} = x~ln(a)\)

Answer 2

@Bzimmerman What have you tried?

Personally, I would multiply by 2^x and see if anything quadratic-looking falls out.

Answer 3

try \[y=2^x\] to make it easier

Answer 4

or don't use that crutch, do what @tkhunny said