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Find all solutions to the equation. cos^2x + 2 cos x + 1 = 0
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Factor the equation.
is it cos=1/2
Nope try again
is it cos - 1/2
and then the solutions are 2pi/3 and 4pi/3
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notice is a quadratic equation, and you factor it just like any other quadratic \(\bf \Large cos^2x + 2 cos x + 1 = 0 \implies a^2+2a+1 = 0\)
i still don't get it
Can you write this ? \[\cos ^{2}x +2\cos x +1 = \left( \cos x + 1 \right)^{2}\]
what do you mean?
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$$ \tt \Large{ \cos^2x+2\cos x + 1 =0\\ Let~u=\cos x\\ Then\\ u^2+2u+1=0\\ (u+1)(u+1)=0\\ (u+1)^2=0\\ (u+1)=0\\ u=-1\\ Sub~back~cos(x)~for~u\\ \cos x=-1\\ This~implies~that~x=-\pi ~\pm~2\pi n,~where~n\in\Bbb N. } $$ Let me know if you have any questions.
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