Question

The longer leg of a right triangle is 2cm less than twice the shorter leg. Find the measure of each leg of the triangle with the smallest possible area.

Answer 1

@dan815

Answer 2

@Jamierox4ev3r

Answer 3

@gsRttN

Answer 4

@Psymon

Answer 5

i need help. Please?

Answer 6

why post the question again...or twice..?

Answer 7

I'm sorry. No one replied with my question in this group. So i asked the question again in geometry group

Answer 8

ok... so draw a picture



find b by using pythagoras' theorem

then you will find the height of the triangle

and the area will be

\[A = \frac{1}{2} bx\]

then find the 1st derivative...

\[\frac{dA}{dx}\]

solve the 1st derivative for x... which will give value of x that creates the minimum area.

then when you know x, you can find all 3 sides of your triangle.

hope this helps

Answer 9

okaay. Thank yoou so much ^_^

Answer 10

the formula of finding b in Pythagorean theorem is b+ sq. root of c^2 - a^2? Am i right?

Answer 11

*=

Answer 12

well b^2 = (2x -2)^2 - x^2

then take the square root.

thats my best guess... I have presumed the longer side in the question is the hypotenuse.

good luck... as its a difficult derivative.

Answer 13

hmm. I see, well thanks for the help ^_^