If I have log base 2 the square root of c is that the same as log base 2 c to the power of 1/2?
\(\large \log_2 \sqrt{c}\)
\(\large (\large \log_2 c)^\frac{1}{2} \)
your two expressions are like above ?
the first is, I am asking to simplify does it become log2 c1/2 (meaning power of 1/2) if that makes sense
\[\log_{2} c ^{1/2}\]
\(\large \log_2 \sqrt{c}\) \( = \large \log_2 (c)^\frac{1}{2}\) \( = \large \frac{1}{2} \log_2 (c)\)
yes you're right :)
Ahhhhh thank you :)
np :) we're donw with that. but as you can see, below two expressions are not same :- \(\large \log_2 \sqrt{c}\) \(\large (\log_2 c)^\frac{1}{2} \)
i hope you see why they're not same
No because then if would be squaring the \[\log_{2} c \] component yes?
perfect, you mean square rooting !
yes
good :)
Thank you again, I struggle a bit with logs sometimes, I am sure it will make sense one day LOL
logs are tricky in the beginning... but i can see you're pretty good in these :)
hahaha thanks :)
you're wlcme !
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