Question

What is the chemical reaction for Mg + NaOH also with the ionic equations and subscripts?

Answer 1

@thomaster

Answer 2

Do you know the products of this reaction?
I can tell you it's a single displacement reaction

Answer 3

The general form is A + BC ---> AC + B

Answer 4

Yes I know them but don't know what form the Na is in :/

Answer 5

Na (?) + Mg(OH)2 (s)

Answer 6

So I can't get the ionic equation...

Answer 7

Mg is either solid or aqueous, It has to react with aqueous sodiumhydroxide. So NaOH (aq)

In water the NaOH will fall apart in \(Na^+\) and \(OH^-\)

The \(\large OH^-\) reacts with the Mg to form \(\large Mg(OH)_2\)

Answer 8

So the chemical equation is

\(\large Mg+2NaOH\to Mg(OH)2+2Na\)

Answer 9

Now we need to write everything as ions to get the ionic equation.

Mg is in elemental form so it stays the same (has 0 charge)
NaOH will fall apart in Na+ and OH-
\(Mg(OH)_2\) will be \(2OH^-\) and \(Mg^{\large 2+}\)
2Na will stay the same too

Answer 10

Mg is a solid we did it in an experiment so it follows that

Answer 11

\(\large Mg(OH)_2\) is a solid too so you can't write it as ions. sorry for that :P

The chemical equation is:
\(\large Mg(s)+2NaOH(aq)\to Mg(OH)_2(s)+2Na\)

When you write all the compounds with (aq) as ions, the equation will be:
\(\large Mg(s)+2Na^++2OH^-(aq)\to Mg(OH)_2(s)+2Na\)

Answer 12

Now you cancel the ones that don't do anything in the reaction. This is sodium for this reaction.
\(\large Mg(s)\cancel{+2Na^+}+2OH^-(aq)\to Mg(OH)_2(s)\cancel{+2Na}\)

Answer 13

You didn't clarify which state Na is in I got a bit side tracked :/

Answer 14

It doesn't matter since Na doesn't participate in the reaction

Answer 15

But I have to write the state otherwise -1 marks D:<

Answer 16

It will be aqueous in that case

Answer 17

But you did the experiment, did you see a gas being produced in the reaction?

Answer 18

No gas :/ maybe just fizzing.

Answer 19

So the Na would have a 1+ charge then?

Answer 20

What's elemental form?

Answer 21

elemental form is when 1 element is free in the equation.
Like the Mg in the reaction.

Answer 22

I don't get it :/

Answer 23

The think i'm confused with.. Solid Magnesium shouldn't react with sodium hydroxide
Since sodium is stronger in the reactivity serie

Answer 24

thing*

Answer 25

O.O

Answer 26

It would reduce NaOH
So you'd get \(\large 2Mg+2NaOH\to 2MgO+2Na+H2\)

Answer 27

I'm getting even more confused

Answer 28

Alright :)

Answer 29

maybe @chmvijay can help...

Answer 30

4NaOH +2Mg ----> 2MgO +2 Na2O + H2

Answer 31

Could you explain why?

Answer 32

ahh and the Na2O will react with water to form NaOH again?

Answer 33

yup :)

Answer 34

So what would be the ionic equation?

Answer 35

4Na + 4OH- +2Mg ------> 2Mg+ + 2Na+ +4O-2 + H2

Answer 36

Thanks @chmvijay

Answer 37

oke Na is the only spectator ion?

Answer 38

wt u mean by spectator ion?

Answer 39

does not participate in the reaction, so you can cancel it

Answer 40

yup :)

Answer 41

\(\large \cancel{4Na^+} + 4OH^- +2Mg \longrightarrow 2Mg^+ \cancel{+ 4Na^+} +4O^{2-} + H2\)

Answer 42

its just understanding them in ionic it doesn't exactly happen or good to write like this:)
2Na+ +O-2 +H + OH _ -----2Na + 2OH-
just he asked i wrote it in ionic form otherwise it wont exist like what u have said already :)

Answer 43

Oke I see :P thanks

Answer 44

@AnImEfReaK Do you understand it now?

Answer 45

No not really... But I'll ask my teacher tomorrow I need someone to explain it in person.

Answer 46

Alright :)