Question

ah

Answer 1

\[\sqrt{x+14}-12=x\]
\[\sqrt{x+14}=x+12\] square both sides get
\[x+4=x^2+24x+144\] solve the quadratic
\[x^2+20x+140=0\] and check the solutions

Answer 2

oops no no
solve the quadratice \[x^2+23x+140=0\]

Answer 3

we can test it
\[\sqrt{-10+14}-12=-10\]
\[\sqrt{4}-12=-10\]
\[2-12=-10\] yup

Answer 4

yw