How would I divide one equation by another?

Question

anonymous · Answer

$$(250*\sin(38)-\sin(\theta)m)/(250*\cos(38)+mcos(\theta)-1000)$$ for example. I never really got my head around this,

anonymous · Answer

would it be like 250∗sin(38)/250∗cos(38) - tan(theta) - 1/1000

anonymous · Answer

Oh gosh I wish I could help.
$$\frac{ (250*\sin(38)-\sin(\theta)m)}{ (250*\cos(38)+mcos(\theta)-1000) }$$
@jim_thompson5910

anonymous · Answer

;)

anonymous · Answer

the real question is this,
0 = 250*cos(38)+fcos(a)-100             -1
0 = 250*sin(38)-sin(theta)f                  -2

I want to find theta and f. so I divide the equations right 2/1

anonymous · Answer

were theta + a are the same variables. soz about that

anonymous · Answer

Since they both equal zero, I think I'd try substitution / transitive property.  The expressions on the right must equal each other.  If a=c and b=c then a=b.