To solve this system using the addition method, you would need to multiply the first equation by what number in order for the x's to add out? 2x + 3y = 8 -6x + 4y = 11
You want the coefficients on x to be opposites. What would you multiply by the first equation so the coefficient on x is the opposite of that on the second equation?
3
@JackJones -3? 0r 3?
3
6 + (-6) = 0
is that it
Idk?? You think you could answer a few more?
if i know it
go ahead and post another question, but first give me a medal and close this one
To solve this system using the addition method, you would need to multiply the first equation by what number in order for the y's to add out? 3x - y = 3 -2x + 2y = 6 3 2 6 none of the above
2
Solve the system using the addition method. 3x + 4y = -10 5x - 2y = 18 What is the x-value in the solution? 2 -2 -4 none of the above
Solve the system using the addition method. 3x + 2y = 10 6x + 4y = 14 What is the solution to the system? (2, 2) (1, 2) Infinite solutions on the line No solution
After those two I'm done.
2 and no solution
Ahh.. so sorry there's one more.
its alright
Solve the system using the addition method. 5x - 2y = 3 2x - y = 0 What is the y-value in the solution? 3 6 -3 none of the above
6
bye
Thank you!!
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