When I plot these points, they are neither parallel or perpendicular. The slopes are WX (2) and YZ (-2). What am I doing wrong? Line WX contains (−1, 2) and (4, 12) Line YZ contains points (−5, 8) and (2, −6). Lines WX and YZ are perpendicular because the slopes are the same parallel because the product of the slopes is −1 perpendicular because the product of the slopes is −1 parallel because the slopes are the same
is not supposed to be the points per se, is supposed to be the lines they make :S
I know. Sorry, that's what I meant.
By plot, I meant I plotted and connected them to their respective lines. That's how I got the slope.
ohh
The create two ~53degree angles and two ~126degree angles.
Which obviously is neither parallel or perpendicular.
well, you're correct, they don't, but that depends on your plotting "scale factor" for each axis, they won't if the scale of the y-axis and x-axis is one to one
for the graphing board that is
I don't understand.
lemme get the equatins and plot them, so I can show you
Oh, real quick, if is straight up and down, it's slope is undefined right? And horizontal is a slope of zero
yes
well, dohh, they're not supposed to be perpendicular :S
darn, my bad, I guess it skipped me for a sec
anyhow, perpendicular lines have NEGATIVE RECIPROCAL slopes what you have there are just negative version of the positive so x is increasing from left to right -x is decreasing from left to right
a perpendicular line to a slope of 2 line will be one with -1/2, negative reciprocal
so -2 is just the "decreasing" version of "2"
In order to make the line perpendicular, it would have to have a slope of -1/2 not -2.
Besides, none of the answers fit. The slopes are not the same. The sum of the slopes is 0.
Any ideas? @Lagoonabarbie
@ababylizard When I plot the points on paper, I got this..
Showing they do intersect perpendicularly, and The slope is -2 for one, and 2 for the other
In order for lines to intersect perpendicularly, they need to be negative reciprocals of one another.
For 2, it has to be -1/2
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