Question

6.) Vera's piggybank contained 9.35 in quarters, dimes, and nickels. there were six more than two times as many nickels as quarters and four less dimes than quarters. how many of each kind of con was there in the bank?????? I don't need a answer. I need two equations..

Answer 1

thanks

Answer 2

your welcome

Answer 3

let

q = number of quarters
d = number of dimes
n = number of nickels

Answer 4

we are told that "there were six more than two times as many nickels as quarters ", so we can say that

q = 2n + 6

Answer 5

there are " four less dimes than quarters.", so

d = q - 4

Answer 6

there is $9.35 in the bank, so

0.25q + 0.10d + 0.05n = 9.35

25q + 10d + 5n = 935 .. multiply everything by 100

Answer 7

ok I made a typo, one sec

Answer 8

The equation q = 2n+6 should be n = 2q+6

Answer 9

25q + 10d + 5n = 935

25q + 10(q - 4) + 5n = 935 ... plug in d = q - 4

25q + 10q - 40 + 5n = 935

25q + 10q + 5n = 935+40

35q + 5n = 975

35q + 5(2q + 6) = 975 ... plug in n = 2q+6

35q + 10q + 30 = 975

45q + 30 = 975

45q = 975 - 30

45q = 945

q = 945/45

q = 21


So there are 21 quarters

Answer 10

n = 2q+6

n = 2*21+6

n = 42 + 6

n = 48

so there are 48 nickels

Answer 11

d = q - 4

d = 21 - 4

d = 17

and there are 17 dimes