Question

Solve the system of the quadratic equations : y=x^2-2x+2
Y-2x=-2

Answer 1

You can solve by substitution:
\[y-2x=-2~~\Rightarrow~~y=2x-2\]
Substituting into the quadratic, you have
\[2x-2=x^2-2x+2\\
x^2-4x+4=0\\
(x-2)^2=0\]
Solve for \(x\), then \(y\).

Answer 2

How do I solve for x and y @sithsandgiggles

Answer 3

From the last line, \((x-2)^2=0\), this is only true for \(x=2\).

Plug this into either original equation to solve for \(y\). The nonquadratic equation is simpler:
\[y-2x=-2~~\Rightarrow~~y-2(2)=-2~~\Rightarrow~~y=\cdots\]

Answer 4

Y=2? @sithsandgiggles

Answer 5

Yep