Question

3
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-2+√13

Answer 1

are you asking for the answer to \[\frac{ 3 }{ -2 + \sqrt{13} }\]?

Answer 2

if so the first step would be to move the \[\sqrt{13}\] to the top by doing \[\frac{ 3 }{ -2 + \sqrt{13} } * \frac{ \sqrt{13} }{ \sqrt{13} } = \frac{ 3 \sqrt{13} }{ -2 + 13 } = \frac{ 3\sqrt{13} }{ 11 }\]

Answer 3

hmmm

Answer 4

that is not going to work sorry

Answer 5

\[\frac{ 3 }{ -2 + \sqrt{13} }\times \frac{-2-\sqrt{13}}{-2-\sqrt{13}}\]is what you need to get rid of the radical in the denominator

Answer 6

yes, multiplying the numerator and the denominator by the radical you are trying to remove does that

Answer 7

\[\sqrt{13} * \sqrt{13} = 13\]