solve 8^1/3
A. the fraction 8 over 3 B. 2.7 C. 2 D. -8
\[8^1/3 =\sqrt[3]{2^{3}}=2\]
how did you get that
by practicing alot :)
that's not what I meant but thanks for the help
buhahaha XD the lil dawg is back!!
lol
Do you understand this concept? \[\Large \sqrt{x}\quad=\quad x^{1/2}\]We can represent the powers AND roots as a fraction. The degree of the root (2 in the example) is the value in the denominator.
can you give an ex.
\[\Large 625^{1/4} \quad=\quad \sqrt[4]{625}\]
See how I wrote the degree of the root as `4` because there was a 4 in the fraction of our exponent? :o
in denominator of our exponent*
yeah thank you that was a good example
Florida also?? Where at? :D I'm in stinky ole Deltona myself -_-
brandon
neato :3
Can you use that exponent idea and it apply it to your 8? :O What would it give you??
c
lol you're just saying that because someone said it earlier -_- I was trying to see if you could write it like this:\[\Large 8^{1/3} \quad=\quad \sqrt[3]{8}\]
But yes that will simplify further to 2 -_- silly dawg
I gotta go
k c:
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