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OpenStudy (anonymous):
How do I find the vertex of the parabola y=x(squared) + 8x +5
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OpenStudy (anonymous):
\(-\frac{b}{2a}\) is the first coordinate of the vertex of \(ax^2+bx+c\) in your case \(a=1,b=8\)
OpenStudy (jdoe0001):
\(\bf \text{vertex of a parabola} \qquad \qquad \left(-\cfrac{b}{2a}, c-\cfrac{b^2}{4a}\right)\)
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