Simple question: How would I complete the square for this?

Question

tracyy · Answer

x^2 − 10x + y^2 − 6y − 30 = 0

tracyy · Answer

What I have so far is: (x^2 - 10x ____) + (y^2-6y ____) - 30 = 0

luigi0210 · Answer

To find C:
$$(\frac{b}{2})^2$$
Right?

tracyy · Answer

I'm supposed to complete the square on x and y terms to find the center and radius of a circle, which I know how to do. I am just stuck at completing the square for this equation.

luigi0210 · Answer

Well move the 30 over and divide b by 2 then square it

debbieg · Answer

For the x portion of the equation, b=-10. Do like @Luigi0210  says, take half of that and square it, add it inside the ( ) AND ALSO ON THE OTHER SIDE.

For the y portion of the equation, b=-6. Again, take half of that and square it, add it inside the ( ) AND ALSO ON THE OTHER SIDE.

Also move the -30 to the other side.

when you do all that (and simplify the RHS, and factor the perfect squares on the LHS) you will have your circle equation.