Denominators with subtraction of polynomials
\[\frac{ 3 }{ 2s+3 }-\frac{ 7 }{(2s+3^{2})}\] I can not figure out the steps to take to get the denominators ready for subtraction
Im sorry the exponent 2 is (2s + 3)^2 for the last denominator
to add or subtract fractions, their denominators must be the same; so let's force it. \[\frac{ 3 }{ 2s+3 }\times \frac{ 2s+3 }{ 2s+3} - \frac{ 7 }{ (2s+3)^2 }\] \[= \frac{ 6s + 9 - 7 }{ (2s+3)^2 }\] notie that we multplied by ONE. so nothing really changed
so the final Answer should be 6s+2/(2s+3)^2?
Becuase that is what I keep getting but they say the right answer is 2(3s+1)/(2s+3)^2
What do you get if you factor the GCF out of 6s+2?
;)
3s
Hmmmm..... what is the GCF of 6s + 2?
2
OK, so factor that out: 6s + 2 = 2(?????)
ah yeah I was taking out everything 2(3s+1) brain not working this is why homework is taking forever tonight =p
Heh... ok, so you see now that the answer above is equivalent to the answer you have?
yeap thank you very much
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