Question

if 289=17^1/5x then x=?

Answer 1

is the equation like this \[289=17^{1/5x}\]

Answer 2

yes

Answer 3

Hey !
What is the question???????????

Answer 4

289=17power 1/5x

Answer 5

Oh !
OK !

Answer 6

\[289 = 17^{1/5x}\]
\[289 = 17^{2}\]
\[17^{2} = 17^{1/5x}\]
What you need to do is to equate the exponents since they have the same base of 17
Can you do it now?

Answer 7

@:Yttrium :
You re falllllllllllllllllllllllllllllllllllllllllllll

Answer 8

s0 10 is the answer

Answer 9

NO :)

Answer 10

1/10, I guess

Answer 11

NO :)

Answer 12

10x = 1, Therefore x = 1/10

Answer 13

@jimra Did you get it?

Answer 14

i also get the same answer .but is it right?

Answer 15

Yes, you can check that by substituting the value of x. Check whether the equation will yield to 289 = 289

Answer 16

right

Answer 17

HEY
look !
First answer this :
17^x=289
What is the x ?!

Answer 18

2

Answer 19

ahh the x is in the denominator...

Answer 20

Yes.

Answer 21

Ok !
Now 2/1.5 =?
?=x
!!!

Answer 22

x in numerator

Answer 23

if x in numerator, therefore 2 = x/5
Hence x = 10
Maybe, i just misinterpret the eq'n. I'm sorry

Answer 24

\[17^2=17^{\frac{x}{5}}\]????

Answer 25

Oh !
OK !
SAY :
Your answer is right !
2.5=10

Answer 26

\[17^2=17^{\frac{1}{5}x}\\log_{17}(17^2)=log_{17}{(17^{\frac{1}{5}x}})\\2=\frac{1}{5}x\\x=10\]

Answer 27

@ Yuttrium : You are true !
@ jimra : The answer is 10 .
!!!

Answer 28

i thought the answer was 2.5 = 10

Answer 29

@jimra, Did you get the concept?

Answer 30

@jimra , Answer to Yttrium question !

Answer 31

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