Question

how to solve this problem

Answer 1

Which problem?

Answer 2

blank multiplied by the quantity of blank=nothing... O.O

Answer 3

lol @abb0t XD

Answer 4

\[V= 4/3 \pi r3\]

Answer 5

this is just the volume formula.. what do you want to solve for?

Answer 6

respect, please @abb0t

Answer 7

oohh ouch :/ so what do you want me to do with this @rosa12 ?

Answer 8

question number 16

Answer 9

http://www.youtube.com/watch?v=e2QKlmMT8II

Answer 10

well what are the two variables in this (hint they are r and h, but I need you to name them for me)

Answer 11

@rosa12

Answer 12

yes

Answer 13

so what are they then? r is _____ and h is ______ . THink of how they affect each other

Answer 14

I think so.

Answer 15

r=radius and h=height.... what happens to the height as radius increases?

Answer 16

I don't know.

Answer 17

where is height (h) in question 16?

Answer 18

yes

Answer 19

question 14 and 16

Answer 20

@Rosa12, look at the wording of question 16: Volume as a function of radius, means we may obtain the volume whatever the radius is. Give any value to radius and you get the volume. Seems like radius is independent (can take any positive value) and volume is dependent (on the radius)

Answer 21

does it make sense?

Answer 22

yes

Answer 23

for number 14

Answer 24

What is it asking? I just see a series of points

Answer 25

each set of ordered pairs represents a function. write a rule that represents the function. (1, 2/3), (2, 4/9), (3, 8/27), (4, 16/81), (5, 32/243)

Answer 26

points can be calculated as:\[P_n=(x_n,y_n)=\left( n,\left( \frac{ 2 }{ 3 } \right)^n \right)\]or if you want to get the function: \[y=\left( \frac{ 2 }{ 3 } \right)^x\]

Answer 27

not

Answer 28

when x=1, y=2/3
when x=2, y=4/9=(2/3)^2
when x=3, y=8/27=(2/3)^3
when x=4, y=16/81=(2/3)^4
when x=5, y=32/243=(2/3)^5

Don´t you see that in order to calculate y for a certain x we just do y=(2/3)^x ?

Answer 29

okay thanks

think you can help in other two questions

Answer 30

shoot! but open new post!

Answer 31

and close this one if solved, please