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f(x)={ kx+1, x<1 and x^2, x is greater or equal to 1} a)find the value of k so that f(x) is continuous at x=1 b) using the value of k found part a) sketch the graph of f(x)
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in order for the function to be continuous, lim f(x) = 1 x->1^-
do you understand?
no:(
this is much easier than it looks put \(x=1\) in both expressions, set them equal, solve for \(k\)
so put k(1)+1=(1)^2 ?
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yep
I got k=0?
me too
me 3
how would I graph this?
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Just make a piecewise graph.... f(x)={ 1, x<1 ={x^2 x>=1 Both pretty basic functions. :)
thank you:) i think i got it now
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