Question

integral of sin^5 3x cos 3x dx ??

Answer 1

let u = sin (3x) and step up from there

Answer 2

3 cos 3x dx = du
dx = 1 /3cos3x . dx
it's true?

Answer 3

keep cos (3x) dx = du/3 and replace to integral

Answer 4

the final answer is 1/6 sin^6 3x +c ??

Answer 5

\[\int \frac{u^5}{3}du=\frac{u^6}{6*3}+C = \frac{sin^6(3x)}{18}+C\]

Answer 6

oh yeaah, thanks a lot :D

Answer 7

yw