A curve is traces by a point P(x,y) which moves such that its distance from the point A(1, -2) is twice its distance from the point B(4, -3). Determine the equation of the curve
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If \(d_1\) is the distance between P and A, and \(d_2\) is the distance between P and B, then you have the following system of equations: \[\begin{cases}d_1=\sqrt{(x-1)^2+(y+2)^2}\\d_2=\sqrt{(x-4)^2+(y+3)^2}\\d_1=2d_2\end{cases}\] It looks like you must solve for \(y\) in terms of \(x\).
Thank you but I am still kinda confused so to go further to find the equation you would?
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