Question

What is the equation of a line perpendicular to the line y = 4/9x - 2 that passes through the point (4,3)?

Options:
y = 9/4x + 6
y = -4/9x - 2
y = -9/4x+ 12
y = -9/4 - 12

Answer 1

the slope equation is y = 4/9x - 2 as in gradient intercept form. (y=mx+b)
after u have your slope formula, do the point-slope formula
y-y1=m(x-x1)

Answer 2

... I don't really get how to turn it into the point slope formula?

Answer 3

(4,3) is (x1,y1)
4/9 is the slope

Answer 4

plug in into this formula: y-y1=m(x-x1)

Answer 5

I just don't get this really and how it relates to the problem...

Answer 6

the equation of a straight line in the form y − y1 = m(x − x1) where m is the slope of the line and (x1, y1) are the coordinates of a given point on the line

Answer 7

I'm sorry your just not really helping me...

Answer 8

I'm not following what you're trying to say..

Answer 9

what part u did't get, ur confusing me?

Answer 10

I don't get how all this is helping me find the line perpendicular to my original line.

Answer 11

A line perpendicular to
y = 4/9x - 2 it's written as y=mx+b where m=slope, b=y-intercept
so has a slope (m) of 4/9
using point (4, 3):
(y - y1) = m(x - x1)
(y - 3) = (4/9)(x - 4)

Answer 12

now simplify

Answer 13

I'm sorry just the way you're saying it isn't making sense at all. I think I just need someone else helping on this one.

Answer 14

ok, good luck