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Mathematics 20 Online
OpenStudy (anonymous):

sqrt

OpenStudy (anonymous):

\[2\sqrt{11}*8\sqrt{22}\]

OpenStudy (anonymous):

You multiply whatever is the inside with the inside, the outside with the outside. Then you look for if whether you can simplify the inside.

OpenStudy (anonymous):

ok so

OpenStudy (anonymous):

Start with the first instruction, what do you get when you multiply \(\sqrt{11} \times \sqrt{22}\)?

OpenStudy (anonymous):

like 15

OpenStudy (anonymous):

\(11 \times 22 = 15\)?

OpenStudy (anonymous):

no 242

OpenStudy (anonymous):

Great! Now Multiply the whole numbers and put it together.

OpenStudy (anonymous):

huh? 16

OpenStudy (anonymous):

Now, but them together...

OpenStudy (anonymous):

multiply them?

OpenStudy (anonymous):

wait is it 15sqrt

OpenStudy (anonymous):

No, put them together - side by side.

OpenStudy (anonymous):

16sqrt 242

OpenStudy (anonymous):

\(16\sqrt{242}\)

OpenStudy (anonymous):

Now, what are the factors of 242?

OpenStudy (anonymous):

It shouldn't be hard, you multiplied \(11 \times 22\) to get it.

OpenStudy (anonymous):

1, 2, 11, 22, 121, and 242.

OpenStudy (anonymous):

I meant prime factorization, sorry. \(11\times 11\times 2\)

OpenStudy (anonymous):

ok?

OpenStudy (anonymous):

Take out a perfect square.

OpenStudy (anonymous):

\(16\times 11\sqrt{2}\)

OpenStudy (anonymous):

176

OpenStudy (anonymous):

Multiply your integers together. Then you will have your answer.

OpenStudy (anonymous):

Now put it together.

OpenStudy (anonymous):

got it. what is \[\sqrt{3}*\]

OpenStudy (anonymous):

\(176\sqrt{2}\)

OpenStudy (anonymous):

\[\sqrt{3}*\sqrt{5}\]

OpenStudy (anonymous):

next question

OpenStudy (anonymous):

Use the same approach. If there is a perfect square factor, pull it out and take the square root.

OpenStudy (anonymous):

is it \[\sqrt{1}\]

OpenStudy (anonymous):

15

OpenStudy (anonymous):

Close, try again..

OpenStudy (anonymous):

\[5\sqrt{3}\]

OpenStudy (anonymous):

Look at it this way.... \(\sqrt{10} \times \sqrt{2}\) \(10 \times 2 = 20\) so... \(\sqrt{10} \times \sqrt{2} = \sqrt{20}\) Use this information to apply to your question.

OpenStudy (anonymous):

\[\sqrt{8}\]

OpenStudy (anonymous):

How did you get that?

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