The position of a softball tossed vertically
upward is described by the equation
y=c1(t)−c2(t^2), wherey
is in meters,tin seconds,c1=6.71 m/s, and c2= 2.39 m/s^2.
Find the ball’s initial speed v0 at t0= 0 s.
Answer in units of m/s

Question

The position of a softball tossed vertically
upward is described by the equation
y=c1(t)−c2(t^2), wherey
is in meters,tin seconds,c1=6.71 m/s, and c2= 2.39 m/s^2.
Find the ball’s initial speed v0 at t0= 0 s.
Answer in units of m/s

dan815 · Answer

are you sure it doesnt say c1=6.71
and c2=2.39

dan815 · Answer

without the units

goformit100 · Answer

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anonymous · Answer

it has the units

cwrw238 · Answer

find the formula for velocity at time t by differentiating  dy/dt

cwrw238 · Answer

are you familiar with calculus?

anonymous · Answer

yes, so you mean it would be c1-c2(2t)?

cwrw238 · Answer

right  so plug in t=0 and you have it

cwrw238 · Answer

ok?

anonymous · Answer

I got 1.93.  Is this not right?

cwrw238 · Answer

v = 6.71 - 2*2.39t

when t = 0 , v = ?

anonymous · Answer

Oh.  Duh

cwrw238 · Answer

lol   - its as simple as that

anonymous · Answer

Excellent.  I was way over thinking it.  Thank you :)

cwrw238 · Answer

yw

anonymous · Answer

how would you find the acceleration at a certain value of t?

anonymous · Answer

velocity/t?

cwrw238 · Answer

acceleration is dv/dt at time t
so differentiate the formula for v

cwrw238 · Answer

where are you?