Question

If θ is drawn in standard position, find its reference angle from θ = − 6π/8

Answer 1

That wording is a big odd, I'm assuming that θ = − 6π/8 ? And we want the reference angle? (And I'm not sure why that isn't fully reduced...??)

But anyway, the reference angle is the angle between the terminal side of θ, and the x-axis (always a positive, acute angle)

Answer 2

So the answer would be 2pi/8 or 1pi/4 depending on if they simplify or not?

Answer 3

Right. I would never say \(2\pi/8\).... I would expect my students to fully simplify. But it is the correct angle, reduced or not. :)