Question

balance this eq. for me please H2SO4+Fe(OH)2=FeSO4=H2O

Answer 1

To help you balance this equation, i think it might be best if you made a table writing down what you have on both sides of the equation.
You have: H\(\sf \color{red}{_2}\)SO\(\sf \color{BLUE}{_4}\) + Fe(OH\(\sf \color{red}{_2}\)) \(\rightarrow\) FeSO\(\sf \color{BLUE}{_4}\) + H\(\sf \color{red}{_2}\)O

Answer 2

Now, in order to balance the chemical equation, you need to have the same number of atoms on both sides. What is being reacted doesn't just magically disappear in a reaction! What goes in \(\sf \color{red}{must}\) also come out!

Notice that you have the same on both sides, except Hydrogen. You have \(\sf \color{purple }{2}\) on the left side, and \(\sf \color{green}{4}\) on the right side! Well, you need to make sure that there is the same amount on both sides.

Now, if you remember from algebra, it follows the distributive property. So, if you say, put a \(\sf \color{red}{2}\) in front of H\(_2\)O, so you have \(\sf \color{red}{2}\)H\(_2\)O, you will have actually \(\sf \color{red}{4}\) HYDROGEN and \(\sf \color{green}{2}\) oxygen atoms total.

But remember IF you change once side, you muast also change the other. If you have for example:
H\(_2\) + 2O\(_2\) \(\rightarrow\) H\(_2\)O

and you are asked to balance it, if you put a 4 in front of H\(_2\)O, LOOK:

H\(_2\) + 2O\(_2\) \(\rightarrow\) \(\sf \color{red}{4}\)H\(_2\)O
you now have \(\sf \color{blue}{8}\) hydrogen on the left, and \(\sf \color{red}{2}\) on the right. Therefore, you must also change the right. Try a \(\sf \color{purple}{3}\)

The final balanced equation is:
\(\sf \color{blue}{4}\)H\(_2\) + 2O\(_2\) \(\rightarrow\) \(\sf \color{red}{4}\)H\(_2\)O

NOW, you have 8 hydrogen on the right, 4 oxygen on the right, and also 8 hydrogen on left and 4 hydrogen on left. BALANCED

Answer 3

H2SO4 + Fe(OH2) → FeSO4 + 2 H2O

As a general rule of thumb is try to always balance the odd number of Oxygen atoms first then work on everything else.