Question

Calculating the average rate of change for 1/(t-1) for t not equal to 1?

Answer 1

Average rate of change?

Over what interval?

Answer 2

The first part of the problem is just to find the average rate of change. Fractions are breaking my brain. I know I have to put it in the formula f(x)=(x+h)-x/h

Answer 3

Provided that the function is continuous over a given interval \([a,b]\), the average rate of change would be
\[\frac{f(b)-f(a)}{b-a}\]
or in your notation, we could let \(h=b-a~~\iff~~b=a+h\), so that you have
\[\frac{f(a+h)-f(a)}{h}\]

Answer 4

You need an interval to find an average. If we're doing it over \((-\infty, 1)\cup (1,\infty)\) that's tricky.

Answer 5

\(\color{blue}{\text{Originally Posted by}}\) @wio
You need an interval to find an average. If we're doing it over \((-\infty, 1)\cup (1,\infty)\) that's tricky.
\(\color{blue}{\text{End of Quote}}\)

Precisely

Answer 6

I see what I did wrong...it's late, but thank you all :)