What is the slope of the line between (3, -4) and (-2, 1)? (1 point)

Question

anonymous · Answer

A.) 1
B.) 2
C.) -1
D.)-2

anonymous · Answer

$$\frac{-4-1}{3-(-2)}$$ is a start

anonymous · Answer

compare how much does x change and how much does y chang at the same time
the equation above does just that:
$$\frac{ y1 - y2 }{ x1 - x2 }$$

anonymous · Answer

Go from this way :
y1-y2/x1-x2 = m
The m is that the slope !
Now get this formula :
y-y1=m(x-x1)

anonymous · Answer

In this question we have this :
-4-1/3+2=-5/5=-1=m
y+4=-1(x+3)
y+4=-x-3
y=-x-7
WE always should have :
y=mx+d

anonymous · Answer

so would it be -2?

anonymous · Answer

(3, -4) and (-2, 1): x1=3, y1=-4
and x2=-2, y2=1

y1--y2 = (-4) -- 1 = -5
x1--x2 =  3 -- (-2) = 5

-5/5 = -1

anonymous · Answer

does it make sense?
well if we start at x=-2, we have y=1. (that is one of the points (-2, 1)

ok, now we go five to the right -
we end up at the second point (3, -4) because x=-2 +5 travelled lands us at x=3

and what happend to y in the meantime? it went from (-2, 1) to (3, -4).
change in y was -5, when we did go 5 x to the right.

Yes, the slope is -1.

anonymous · Answer

when I compare Y in the second last paragraph I always look at the second component
so I compare (x, 1) and (x, -4)