Question

Please help. Photo attached!

Answer 1

ASAP please

Answer 2

If you take any pair point in table 3 you'll see that for every 2 units in x, y is increasing by 5 units
The linear function is defined by (y-y1) = m(x-x1)
where (x1, y1) match with any random pair in table and m is the slope defined by:\[m=\frac{ y2-y1 }{ x2-x1 }\]
where (x1, y1) is any point at the left and (x2, y2) is any point at the right

Answer 3

ok so Table 3 is Linear... what is the equation of the linear function represented by that table? @ruizgeorge

Answer 4

solving m for two random point in table
Let's take (x1, y1) = (2,1) and (x2, y2) = (4,6)
\[m = \frac{ 6-1 }{ 4-2 } = \frac{ 5 }{ 2 }\]
Now take (x1, y1) to the equation with m
\[y-1 = \frac{ 5 }{ 2 } (x-2)\]
Solve for y !

Answer 5

6- 1 = 5/2 (4-2) @ruizgeorge am i right?

Answer 6

Nope
Just let y as y and x as x

Answer 7

..... my so is the 4 actually 6? and 6 actully 4?

Answer 8

4-1 = 5/2 (6-2) ?

Answer 9

\[y = \frac{ 5 }{ 2 } x - \frac{ 5 }{ 2 } (2) + 1\]
solve and simplify

Answer 10

i really dont know.

Answer 11

it's done
\[y-y1 = m(x-x1)\]
leads to the equation
\[y-1=\frac{ 5 }{ 2 } (x-2)\]
and solving for y:
\[y = \frac{ 5 }{ 2 }x - 4\] (This is the linear equation for data in table #3)
and that's all!

Answer 12

Oh wow.... thanks!