Question

Help me with graphing please? :/

Answer 1

Post the graph :)

Answer 2

I need to find the solution
\[y \le - 1/2x - 8\]
\[y \ge -1/2\]

Answer 3

augh\[y \ge -1/2x + 5\] is what the second should be

Answer 4

What are you trying to get? The first graph is going to be Full line over -15x and -8Y
Im doing the second one now :D

Answer 5

The second one is going to be Posotive 5 going up and positive 10 on the right side incase your not sure about the Y and X's yet :)

Answer 6

Shaded in on both with line NOT dotted I repeat NOT dotted full lines on both inequalitys :)

Answer 7

*Inequality's

Answer 8

I need to "Give one point in the solution area or state no solution." as my answer

Answer 9

Can you copy and paste the question "word for word"?

Answer 10

first: graphe both inequalities like regular lines
\[y= (-1/2)x - 8\] and \[y= (-1/2)x + 5\] both inequalities will be solid lines. you need to determine where the shaded region is going to be by plugging in some numbers. when you get your result, you need to ask yourself is this <= or >=. where ever the result is true, shade that entire region. do this for both inequalities. the intersection is the solution.

Answer 11

Your looking for the intersection of them?

Answer 12

ignore the file name xD

Answer 13

I guess now we know what you're having for lunch :P

Answer 14

lol. What are the possible answers?

Answer 15

XD nice jdoe, and there are no possible answers, I have to come up with the answer

Answer 16

It's a word problem?

Answer 17

not really? I have to graph the two equations then tell her what teh solution to them is

Answer 18

hmmm, is rather simple, since it's already solved for "y", or in so-called slope-intercept form anyhow, so graph both lines first, that is \(\bf y = \color{blue}{-\cfrac{1}{2}}x-8 \qquad y = \color{blue}{-\cfrac{1}{2}}x+5\)

btw, notice the slopes for both graphs

Answer 19

The slope for both graphs is -1/2 I'll try to draw a graph is that right?

Answer 20

Yes! IT IS! :D

Answer 21

Is your teacher asking you what type of lines these are? If so. They are Parallel lines lol

Answer 22

xD Thanks Blakarican, Jdoe, if its right does that mean there's no solution?

Answer 23

yes, now test POINTS NOT IN THE LINEs, for the shading
say let's test in between for both, let's say the point .... in between of (0, 2)
\(\bf y \le -\cfrac{1}{2}x-8 \implies 2 \le -\cfrac{1}{2}0-8 \implies 2 \le-8\)

now, is 2 really less or equal to -8? no, thus is false, thus the middle region is false for that line, if that's false, that means the OTHER SIDE OF IT, is the TRUE part, so the shading is above it

Answer 24

other side of which line?

Answer 25

I tested it the -8 one so that'd be