Question

conjugate axis on the x-axis, one focus at (0, √13), equation of one directrix y= 9√13 / 13. HELP PLEASE

Answer 1

what you need equation of parabola?

Answer 2

hyperbola..

Answer 3

since x- axis is your conjugate you get the two conics one on top and one in the bottom

Answer 4

given eccentricity,e=9/sqrt13
b^2=a^2(e^2-1)

Answer 5

no background about conics.. im sorry

Answer 6

standard form is (x/a)^2-(y/b)^2=1
therefore your equation will be of the form (bx)^2-(ay)^2=(ab)^2

Answer 7

yes yes..

Answer 8

foci: (h, k + c), (h, k - c)
c=sqrt(a^2+b^2)
(h,k) will be your vertex
equation is (y-k)^2/a^2-((x-h)/b)^2=1

Answer 9

there is a change in slope (negative ) because x axis is the conjugate axis

Answer 10

it would be imparted with parabola. i think?