Question

Differentiate the Functions. f(u)= (ln(u)/1+ln(2u))

Answer 1

is this ln(u)/1?

Answer 2

cause ln(u)/1=ln(u)...

Answer 3

f(u)=ln(u)/(1+ln(2u))

Answer 4

okay. for these problems I'd probably brute force it out with the quotient rule, but there maybe a better way...

Answer 5

I was going to say quotient rule, too. YOu could rewrite the den'r as 1 + ln2 +ln(u) for ease in the differentiation step. Avoids the chain rule.

Answer 6

lol, forgot the rules for logarithms :S

Answer 7

Oh right, lol... you had me convinced, but yeah, the product rule, not the exponent thing, applies here. :)

Answer 8

so glad I'm out of calculus hehe - no loggy log laws in discrete

Answer 9

so can someone work it out for me because I keep trying and am not getting the right answer

Answer 10

How about if you show us what you did, and we can tell you where you're going wrong.

Answer 11

ill try again later. I dont feel like typing it all out