Question

question 5, help please

Answer 1

for each one, you can plot a bunch of points and draw a curve through those points

Answer 2

so for instance, if x = 0, then

y = x^3

y = 0^3

y = 0

so (0,0) is on y = x^3

and...

if x = 1, then

y = x^3

y = 1^3

y = 1

and (1,1) is also on y = x^3

if x = 2, then

y = x^3

y = 2^3

y = 8

which means (2,8) is also on y = x^3

Answer 3

is there any quicker way? that seems very tedious?

Answer 4

so plot those points (and more for better accuracy), then draw a curve through them to graph the function

Answer 5

well you could graph the basic shape from memory, the equation y = x^3 is a cubic which looks like this

Answer 6

ok thx :) ill just learn off the shape of those graphs then, thx a bunch !

Answer 7

they don't have to be accurate since they rough sketches, so you can use this quicker method

you're welcome

Answer 8

ok thx again!

Answer 9

np