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Mathematics 21 Online
OpenStudy (anonymous):

help! Anita made a wax model of a rolling pin of diameter 6 cm. The rolling pin was shaped like a right circular cylinder with a right circular cone at each end as shown below. A rolling pin shaped as a cylinder with conical ends. The length of the cylindrical part is 9 cm, the slant height of each cone is 4 cm and the diameter of the rolling pin is 6 cm. http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_0810_19/image0014e68d166.jpg What was the total surface area of the rolling pin? write out steps please

OpenStudy (jdoe0001):

url requires login, try with a screenshot instead

OpenStudy (anonymous):

surface area of the cylinder (without its bases) : 2*pi*r*h surface area of each of the cones (without base) : pi*r*s (s=slant height) can you do it now ?

OpenStudy (anonymous):

here it is

OpenStudy (anonymous):

@jdoe0001

OpenStudy (anonymous):

it is ok.. look at what i wrote .. the text was informative we dont really need the picture

OpenStudy (anonymous):

so the surface area of the cylinder would be 169.56 and the surface area of the cone is 37.68 but now what do i do to find the total surface area to i add them together?

OpenStudy (anonymous):

well first notice that we ignore the bases since the base of each cones touches a different base of the cylinder

OpenStudy (anonymous):

now, we have 1 cylinder and 2 cones .. so what we should do ?

OpenStudy (anonymous):

ummm would you subtract the base from each one?

OpenStudy (anonymous):

now as you can see the formulas that i wrote are formulas for surface areas WITHOUT bases

OpenStudy (anonymous):

so no worries about the bases anymore. i just wanted to point it out

OpenStudy (anonymous):

you wrote "so the surface area of the cylinder would be 169.56 and the surface area of the cone is 37.68 but now what do i do to find the total surface area to i add them together?" now we have surface area of the cylinder (without bases) : 169.56 and surface area of one cone (without base) : 37.68 we have 1 cylinder and 2 cones .. what we should do then ?

OpenStudy (anonymous):

add them together

OpenStudy (anonymous):

169.56 + 37.68 ? what about the second cone ?

OpenStudy (anonymous):

add 37.68 to it again

OpenStudy (anonymous):

correct

OpenStudy (anonymous):

to make it 169.56+37.68+37.68= 244.92?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

now just one moment.. what if you had only one cone ?

OpenStudy (anonymous):

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OpenStudy (anonymous):

then it would be 207.24

OpenStudy (anonymous):

no, since we need to add one base (you see the left base is part of the surface now!)

OpenStudy (anonymous):

when we had two cones, no one of the bases (nor the cylinder and not the cones) were part of the surface of the shape now, we have one base that is part of the surface of the shape

OpenStudy (anonymous):

sorry for my English by the way

OpenStudy (anonymous):

so would you add 6 to it because that is the diameter of it?

OpenStudy (anonymous):

no, the area of one base of the cylinder (which is in fact area of a circle ) = pi*r^2

OpenStudy (anonymous):

so would you add 28.26 to it?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

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