Question

Oxidation and reduction half-reactions...

A) 2H2 + O2 =>2H2O
Oxidation half-reaction:
Reduction half-reaction:

B) MnO2(s) + 4HCl(aq) => MnCl2(aq) + Cl2(g) + 2H2O(l)
Oxidation half-reaction:
Reduction half-reaction

3) S(s)+ 6HNO3(aq) => SO3(g)+ 3H2O(l) + 6NO2(g)
Oxidation half-reaction:
Reduction half reaction:

*Best response and I will become a fan to whoever helps me with this.*
Thanks :)

Answer 1

i'm not gonna give you the answers, but i can show you how to do it, if you'd like.

Answer 2

It's simple.

Start by assigning oxidation states/numbers to all the atoms in the species.
Determine which underwent oxidation (oxidation number became more negative)
Determine which underwent reduction (oxidation number became more positive)
write them as oxidation half reaction: \(A\rightarrow A^{n+} +n\;e^-\)
or reduction half reaction: \(A^{n+} +n\;e^-\rightarrow A\)

Answer 3

Good call Aaron. So Emily, in the equation, 2H2 + O2 =>2H2O
you need to figure out whether H or O loses the electrons (Loss of Electrons = Oxidation) and which gains. (Gain of Electrons = GER). When O2 goes to H2O, does it gain or lose electrons?

Answer 4

Does it gain? @Preetha