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Mathematics 21 Online
OpenStudy (anonymous):

Attachment below: geometry

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910

jimthompson5910 (jim_thompson5910):

first we need to find the length of AC

jimthompson5910 (jim_thompson5910):

so use the distance formula for this

OpenStudy (anonymous):

what numbers do we input though?

jimthompson5910 (jim_thompson5910):

the coordinates of A and C

OpenStudy (anonymous):

is it 7 or 6 for A?

OpenStudy (anonymous):

C is 4 or 4.something?

jimthompson5910 (jim_thompson5910):

what is the ordered pair for point A

OpenStudy (anonymous):

6, 4?

jimthompson5910 (jim_thompson5910):

you sure?

jimthompson5910 (jim_thompson5910):

again I'm asking for point A

OpenStudy (anonymous):

No, I'm not.. I'm not sure what point A is at.

jimthompson5910 (jim_thompson5910):

you start at the origin (0,0) this is where the x and y axis cross

jimthompson5910 (jim_thompson5910):

now how many spaces must you go to the left to get to point A? how many spaces do you go up or down?

OpenStudy (anonymous):

Yes.. I understand how to find it but I'm not sure if it's 6 or 7.

OpenStudy (anonymous):

-7

jimthompson5910 (jim_thompson5910):

it's 6 units to the left so A is the point (-6, 0)

OpenStudy (anonymous):

yeah.. I forgot the negative sign. so -6,

jimthompson5910 (jim_thompson5910):

the y coordinate is 0 since you don't go up or down and you stay on the x axis

jimthompson5910 (jim_thompson5910):

what is point C

OpenStudy (anonymous):

don't we have to find AB, BC, and AC?

jimthompson5910 (jim_thompson5910):

no all we need right now is AC

OpenStudy (anonymous):

why are we doing one point at a time? for the form.?

OpenStudy (anonymous):

ohhh

jimthompson5910 (jim_thompson5910):

we need AC because we're trying to prove that some new line segment is parallel to AC and it's half the length so we need the length of AC first

jimthompson5910 (jim_thompson5910):

to find the length of AC, we use the distance formula but to do that, we need the points A and C (the x,y form of both points)

OpenStudy (anonymous):

okay.. but how do I figure out C? considering it's not an even number

jimthompson5910 (jim_thompson5910):

C is the point (0,-4) you start at (0,0) then go down 4 ticks or units to land on C

jimthompson5910 (jim_thompson5910):

I honestly don't know what the -6.67 is referring to

OpenStudy (anonymous):

so it's -6,-4?

jimthompson5910 (jim_thompson5910):

no (0,-4) notice how you don't go left/right from the origin to get to C

OpenStudy (anonymous):

no, I mean for AC....

jimthompson5910 (jim_thompson5910):

oh AC is the distance from A to C

jimthompson5910 (jim_thompson5910):

when I say AC, I really mean "find the length of segment AC"

OpenStudy (anonymous):

Now, I'm lost. I just meant the coordinates...

jimthompson5910 (jim_thompson5910):

we know that A is the point (-6,0) C is the point (0,-4) the distance from A to C is ????

OpenStudy (anonymous):

Should I use a formula or just subtract?

jimthompson5910 (jim_thompson5910):

I'd use the formula so you get more practice using it

OpenStudy (anonymous):

one sec

jimthompson5910 (jim_thompson5910):

ok

OpenStudy (anonymous):

d = sqrt(-6, 0)^2 + (0 - (-4))^2??

jimthompson5910 (jim_thompson5910):

i think you meant to say -6 - 0 instead of -6, 0

jimthompson5910 (jim_thompson5910):

if so, then you are correct so far

OpenStudy (anonymous):

d = sqrt(x2-x1)^2+(y2-y1)^2 d = sqrt(-6 - 0)^2 + (0 - (-4))^2 d = sqrt(-6)^2 + (4)^2 d = sqrt(36) + (16) d = sqrt(52) d = 7.2

jimthompson5910 (jim_thompson5910):

good

jimthompson5910 (jim_thompson5910):

now you must find the midpoints of AB and BC

OpenStudy (anonymous):

Do I do AB now?

jimthompson5910 (jim_thompson5910):

yes you need the midpoint of AB you do NOT need to find the distance from A to B

OpenStudy (anonymous):

how do I do this?

jimthompson5910 (jim_thompson5910):

use the midpoint formula http://www.purplemath.com/modules/midpoint.htm the link above explains what the formula is and how it works

OpenStudy (anonymous):

Yeah but what numbers do I put in? I actually remember this formula

jimthompson5910 (jim_thompson5910):

the coordinates of A and B

OpenStudy (anonymous):

0,4 ?

jimthompson5910 (jim_thompson5910):

that's point B

jimthompson5910 (jim_thompson5910):

A(-6,0) B(0,4)

jimthompson5910 (jim_thompson5910):

now use the midpoint formula

OpenStudy (anonymous):

-6 + 0/2, 0 + 4/2?

jimthompson5910 (jim_thompson5910):

keep going

OpenStudy (anonymous):

-3, 2

jimthompson5910 (jim_thompson5910):

good, that's the midpoint of AB let's call this point M

jimthompson5910 (jim_thompson5910):

what is the midpoint of BC?

OpenStudy (anonymous):

is it 0,4 and 0,4?

OpenStudy (anonymous):

not the midpoint

jimthompson5910 (jim_thompson5910):

B(0,4) C(0,-4) midpoint is ????

OpenStudy (anonymous):

2, -2?

jimthompson5910 (jim_thompson5910):

no

OpenStudy (anonymous):

I must be doing something wrong

jimthompson5910 (jim_thompson5910):

the x coordinates of the two points are 0 and 0 add them, divide by 2 (0+0)/2 0/2 0 so the x coordinate of the midpoint is 0

jimthompson5910 (jim_thompson5910):

what is the y coordinate of the midpoint ?

OpenStudy (anonymous):

I see what I did wrong. It's 0, -2

jimthompson5910 (jim_thompson5910):

no it's not

jimthompson5910 (jim_thompson5910):

the y coordinates are 4 and -4 they add to 0 cut this in half to get 0

jimthompson5910 (jim_thompson5910):

so the midpoint is (0,0)

jimthompson5910 (jim_thompson5910):

so let the point N be the midpoint of BC this means N is the point (0,0)

jimthompson5910 (jim_thompson5910):

you have two new points: M(-3,2) and N(0,0) you need to do two things now a) find the slope of MN b) find the length of MN

OpenStudy (anonymous):

one sec

jimthompson5910 (jim_thompson5910):

ok

OpenStudy (anonymous):

My computer froze and I lost all my answers on the test. I'll come back to this question after.

OpenStudy (anonymous):

Hey, could we work from a certain step?

jimthompson5910 (jim_thompson5910):

I'm sorry, I cannot help you on tests since it's something you should do on your own.

OpenStudy (anonymous):

It's not a test... I was talking about something else. Not what I was consulting with you with.

OpenStudy (anonymous):

This is for practice.

jimthompson5910 (jim_thompson5910):

alright

OpenStudy (anonymous):

How do we find the slope? and the test I was doing was for English

jimthompson5910 (jim_thompson5910):

what are the two points?

OpenStudy (anonymous):

M(-3,2) and N(0,0)?

jimthompson5910 (jim_thompson5910):

use the slope formula to get this m = (y2-y1)/(x2-x1) m = (0-2)/(0-(-3)) m = (0-2)/(0+3) m = -2/3

OpenStudy (anonymous):

so that's for one side or both?

jimthompson5910 (jim_thompson5910):

I'm not sure what you mean

jimthompson5910 (jim_thompson5910):

is this for the same problem? or a different problem?

OpenStudy (anonymous):

Same. There was two points so I was wondering.

jimthompson5910 (jim_thompson5910):

oh that's right you needed to find the slope of MN

OpenStudy (anonymous):

Now I'm confused hahaha

jimthompson5910 (jim_thompson5910):

and yes you need two points to find the slope one is not enough

OpenStudy (anonymous):

can we start from when we found N?

jimthompson5910 (jim_thompson5910):

yeah it doesn't help that this happened nearly 5 hours ago

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