Mathematics
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OpenStudy (anonymous):
Attachment below: geometry
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OpenStudy (anonymous):
OpenStudy (anonymous):
@jim_thompson5910
jimthompson5910 (jim_thompson5910):
first we need to find the length of AC
jimthompson5910 (jim_thompson5910):
so use the distance formula for this
OpenStudy (anonymous):
what numbers do we input though?
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jimthompson5910 (jim_thompson5910):
the coordinates of A and C
OpenStudy (anonymous):
is it 7 or 6 for A?
OpenStudy (anonymous):
C is 4 or 4.something?
jimthompson5910 (jim_thompson5910):
what is the ordered pair for point A
OpenStudy (anonymous):
6, 4?
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jimthompson5910 (jim_thompson5910):
you sure?
jimthompson5910 (jim_thompson5910):
again I'm asking for point A
OpenStudy (anonymous):
No, I'm not.. I'm not sure what point A is at.
jimthompson5910 (jim_thompson5910):
you start at the origin (0,0)
this is where the x and y axis cross
jimthompson5910 (jim_thompson5910):
now how many spaces must you go to the left to get to point A?
how many spaces do you go up or down?
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OpenStudy (anonymous):
Yes.. I understand how to find it but I'm not sure if it's 6 or 7.
OpenStudy (anonymous):
-7
jimthompson5910 (jim_thompson5910):
it's 6 units to the left
so A is the point (-6, 0)
OpenStudy (anonymous):
yeah.. I forgot the negative sign. so -6,
jimthompson5910 (jim_thompson5910):
the y coordinate is 0 since you don't go up or down and you stay on the x axis
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jimthompson5910 (jim_thompson5910):
what is point C
OpenStudy (anonymous):
don't we have to find AB, BC, and AC?
jimthompson5910 (jim_thompson5910):
no all we need right now is AC
OpenStudy (anonymous):
why are we doing one point at a time? for the form.?
OpenStudy (anonymous):
ohhh
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jimthompson5910 (jim_thompson5910):
we need AC because we're trying to prove that some new line segment is parallel to AC and it's half the length
so we need the length of AC first
jimthompson5910 (jim_thompson5910):
to find the length of AC, we use the distance formula
but to do that, we need the points A and C (the x,y form of both points)
OpenStudy (anonymous):
okay.. but how do I figure out C? considering it's not an even number
jimthompson5910 (jim_thompson5910):
C is the point (0,-4)
you start at (0,0) then go down 4 ticks or units to land on C
jimthompson5910 (jim_thompson5910):
I honestly don't know what the -6.67 is referring to
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OpenStudy (anonymous):
so it's -6,-4?
jimthompson5910 (jim_thompson5910):
no (0,-4)
notice how you don't go left/right from the origin to get to C
OpenStudy (anonymous):
no, I mean for AC....
jimthompson5910 (jim_thompson5910):
oh AC is the distance from A to C
jimthompson5910 (jim_thompson5910):
when I say AC, I really mean "find the length of segment AC"
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OpenStudy (anonymous):
Now, I'm lost. I just meant the coordinates...
jimthompson5910 (jim_thompson5910):
we know that A is the point (-6,0)
C is the point (0,-4)
the distance from A to C is ????
OpenStudy (anonymous):
Should I use a formula or just subtract?
jimthompson5910 (jim_thompson5910):
I'd use the formula so you get more practice using it
OpenStudy (anonymous):
one sec
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jimthompson5910 (jim_thompson5910):
ok
OpenStudy (anonymous):
d = sqrt(-6, 0)^2 + (0 - (-4))^2??
jimthompson5910 (jim_thompson5910):
i think you meant to say -6 - 0 instead of -6, 0
jimthompson5910 (jim_thompson5910):
if so, then you are correct so far
OpenStudy (anonymous):
d = sqrt(x2-x1)^2+(y2-y1)^2
d = sqrt(-6 - 0)^2 + (0 - (-4))^2
d = sqrt(-6)^2 + (4)^2
d = sqrt(36) + (16)
d = sqrt(52)
d = 7.2
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jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
now you must find the midpoints of AB and BC
OpenStudy (anonymous):
Do I do AB now?
jimthompson5910 (jim_thompson5910):
yes you need the midpoint of AB
you do NOT need to find the distance from A to B
OpenStudy (anonymous):
how do I do this?
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OpenStudy (anonymous):
Yeah but what numbers do I put in? I actually remember this formula
jimthompson5910 (jim_thompson5910):
the coordinates of A and B
OpenStudy (anonymous):
0,4 ?
jimthompson5910 (jim_thompson5910):
that's point B
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jimthompson5910 (jim_thompson5910):
A(-6,0)
B(0,4)
jimthompson5910 (jim_thompson5910):
now use the midpoint formula
OpenStudy (anonymous):
-6 + 0/2, 0 + 4/2?
jimthompson5910 (jim_thompson5910):
keep going
OpenStudy (anonymous):
-3, 2
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jimthompson5910 (jim_thompson5910):
good, that's the midpoint of AB
let's call this point M
jimthompson5910 (jim_thompson5910):
what is the midpoint of BC?
OpenStudy (anonymous):
is it 0,4 and 0,4?
OpenStudy (anonymous):
not the midpoint
jimthompson5910 (jim_thompson5910):
B(0,4)
C(0,-4)
midpoint is ????
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OpenStudy (anonymous):
2, -2?
jimthompson5910 (jim_thompson5910):
no
OpenStudy (anonymous):
I must be doing something wrong
jimthompson5910 (jim_thompson5910):
the x coordinates of the two points are 0 and 0
add them, divide by 2
(0+0)/2
0/2
0
so the x coordinate of the midpoint is 0
jimthompson5910 (jim_thompson5910):
what is the y coordinate of the midpoint ?
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OpenStudy (anonymous):
I see what I did wrong. It's 0, -2
jimthompson5910 (jim_thompson5910):
no it's not
jimthompson5910 (jim_thompson5910):
the y coordinates are 4 and -4
they add to 0
cut this in half to get 0
jimthompson5910 (jim_thompson5910):
so the midpoint is (0,0)
jimthompson5910 (jim_thompson5910):
so let the point N be the midpoint of BC
this means N is the point (0,0)
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jimthompson5910 (jim_thompson5910):
you have two new points: M(-3,2) and N(0,0)
you need to do two things now
a) find the slope of MN
b) find the length of MN
OpenStudy (anonymous):
one sec
jimthompson5910 (jim_thompson5910):
ok
OpenStudy (anonymous):
My computer froze and I lost all my answers on the test. I'll come back to this question after.
OpenStudy (anonymous):
Hey, could we work from a certain step?
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jimthompson5910 (jim_thompson5910):
I'm sorry, I cannot help you on tests since it's something you should do on your own.
OpenStudy (anonymous):
It's not a test... I was talking about something else. Not what I was consulting with you with.
OpenStudy (anonymous):
This is for practice.
jimthompson5910 (jim_thompson5910):
alright
OpenStudy (anonymous):
How do we find the slope? and the test I was doing was for English
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jimthompson5910 (jim_thompson5910):
what are the two points?
OpenStudy (anonymous):
M(-3,2) and N(0,0)?
jimthompson5910 (jim_thompson5910):
use the slope formula to get this
m = (y2-y1)/(x2-x1)
m = (0-2)/(0-(-3))
m = (0-2)/(0+3)
m = -2/3
OpenStudy (anonymous):
so that's for one side or both?
jimthompson5910 (jim_thompson5910):
I'm not sure what you mean
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jimthompson5910 (jim_thompson5910):
is this for the same problem? or a different problem?
OpenStudy (anonymous):
Same. There was two points so I was wondering.
jimthompson5910 (jim_thompson5910):
oh that's right you needed to find the slope of MN
OpenStudy (anonymous):
Now I'm confused hahaha
jimthompson5910 (jim_thompson5910):
and yes you need two points to find the slope
one is not enough
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OpenStudy (anonymous):
can we start from when we found N?
jimthompson5910 (jim_thompson5910):
yeah it doesn't help that this happened nearly 5 hours ago