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Eliminate the parameter. x = 5 cos t, y = 5 sin t
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\[\cos t=\frac{ x }{ 5 },\sin t=\frac{ y }{ 5 } squareand add\] you will get the answer.
x^2+y^2=25?
good.
Do mind demonstrating to me how you actually got the answer, I want to compare my way with yours, if you do not mind. Also, I want to Thank You for helping me with the previous question you aided me with earlier.
\[\cos ^{2}t+\sin ^{2}t=\left( \frac{ x }{5 } \right)^{2}+\left( \frac{ y }{ 5 } \right)^{2}\] \[1=\frac{ x ^{2} }{ 25 }+\frac{ y ^{2} }{ 25} ,or x ^{2}+y ^{2}=25\]
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