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How to convert x=3+3cos(theta) and y=2+5sin(theta) to rectangular by eliminating the parameter
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\[ \frac{x-1}3=\cos(\theta) \]
\[ \sin(\theta) =\pm\sqrt{1-\cos^2(\theta)} = \pm \sqrt{1-\left(\frac{x-1}3\right)^2} \]
\[ y=2\pm 5\sqrt{1-\left(\frac{x-1}3\right)^2} \]
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This parametrization can only be regularized for certain intervals of \(\theta\), otherwise it stops being a function.
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There may be a better way of doing this..
\[ \frac{x-1}{3}=\cos(\theta)\\ \frac{y-2}{5} = \sin(\theta)\\ \left(\frac{x-1}{3}\right)^2+\left(\frac{y-2}{5}\right)^2 = \cos^2(\theta)+\sin^2(\theta) = 1 \]
So a less pelletty answer is just\[ \left(\frac{x-1}{3}\right)^2+\left(\frac{y-2}{5}\right)^2 = 1 \]
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