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Solve 4^(x) = 12
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divide 12 by 4 and you get x= 3
you have to use the log( ) function. a^x = b => alog( a^x) = alog(b) => x = alog(b)
\(\bf 4^{x} = 12\\\quad \\ \textit{log cancellation rule of } log_aa^x = x\\\quad \\ log_4( 4^{x}) = log_4(12) \implies x = log_4(12)\\ \quad \\ \textit{using log change of base rule of } log_ab = \cfrac{log_cb}{log_ca}\\ \quad \\ x = log_4(12) \implies x = \cfrac{log_{10}4}{log_{10}12}\)
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