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Chemistry 16 Online
OpenStudy (anonymous):

Help please? Link is below...

OpenStudy (anonymous):

OpenStudy (anonymous):

@MarcLeclair ??? Can you help with this one too? If you can do you need more info?

OpenStudy (anonymous):

its odd youre doing this without knowing the ice process... haha In this part, the Eq. Point will be at 7. Why? because it is a strong base mixed with a strong acid, therefore they will neutralize each other. So for instance, the curve will start off very slow and spike up and finish up very slowly ( kinda like a big s)

OpenStudy (anonymous):

do you understand to finish the rest?

OpenStudy (anonymous):

No. I don't understand where you got 7 @MarcLeclair

OpenStudy (anonymous):

okay well lets say you have a strong base of ph 14, and strong acid of ph 1, when you mix both together, the ph of the resultant solution ( of the product) will be 7 because both solutions neutralize each other.

OpenStudy (anonymous):

so lets say I use a strong acid with a weak base, than the ph of the resulting solution will be under 7 ( always depending on the 2 solutions used) could be like ph=5 if the initial solutions were ph=2 and ph=10, I mean it's all depending.

OpenStudy (anonymous):

Okay... @MarcLeclair

OpenStudy (anonymous):

What I am trying to say is when two solutions are mixed together, they will neutralize each other. Kinda like "counter" each other effect. it would be like mixing a hot drink with a cold drink, the result will be "lukewarm". Samething goes with High ph with low ph, (acidic with basic solutions) the result will be a non-acidic and non-basic solution.

OpenStudy (anonymous):

Oh okay @MarcLeclair

OpenStudy (anonymous):

I mean you can notice that with the rest of the questions...strong acid with weak base will give you an equivalence point lower than 7=ph, for the other one ( strong base and weak acid) it will give a ph>7 for weak and weak, it won't really change. I can't give numbers because we're talking in general in your homework question.

OpenStudy (anonymous):

OKay. I think I understand now. @MarcLeclair

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